7x^2+3x-4=-

Solution for 7x^2+3x-4=- equation:

7x^2+3x-4=-

We move all terms to the left:

7x^2+3x-4-(-)=0

We add all the numbers together, and all the variables

7x^2+3x-4-0=0

We add all the numbers together, and all the variables

7x^2+3x-4=0

a = 7; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·7·(-4)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-11}{2*7}=\frac{-14}{14}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+11}{2*7}=\frac{8}{14}
=4/7
$